(x^3+3x^2-4x-12)/(3x^2-27)

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Solution for (x^3+3x^2-4x-12)/(3x^2-27) equation: 


D( x )

3*x^2-27 = 0

3*x^2-27 = 0

3*x^2-27 = 0

3*x^2 = 27 // : 3

x^2 = 9

x^2 = 9 // ^ 1/2

abs(x) = 3

x = 3 or x = -3

x in (-oo:-3) U (-3:3) U (3:+oo)

(x^3+3*x^2-(4*x)-12)/(3*x^2-27) = 0

(x^3+3*x^2-4*x-12)/(3*x^2-27) = 0

x^3+3*x^2-4*x-12 = 0

x^3+3*x^2-4*x-12

x^2*(x+3)-4*x-12

x^2*(x+3)-4*(x+3)

(x^2-4)*(x+3)

((x^2-4)*(x+3))/(3*x^2-27) = 0

( x+3 )

x+3 = 0 // - 3

x = -3

( x^2-4 )

1*x^2 = 4 // : 1

x^2 = 4

x^2 = 4 // ^ 1/2

abs(x) = 2

x = 2 or x = -2

x in { -3} 

x in { 2, -2 }

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